Question

given a2=37;d=3 find a and s12​

Answer 1

a2 = 37, d = 3

we know that,

a2 = a + d

37 = a + 3

a = 37 - 3

a = 34

to find the sum till 12th term we need to have 2 terms 1st and 12th.

we know that a12 = a +11d

a12 = 34 + 33

a12 = 67

we now that sn = n/2 (a+l)

n = 12, a= 34 and l = 67

s12 = 12/2 ( 34 + 67)

s12 = 6*101

s12 = 606