Math, asked by srishtisinghyksns, 8 months ago

Given a2 + b2 = 1, c2 + d2 = 1, p2 + q2 = 1,where all numbers are real, then
(1) ab + cd + pq >= 1 (2) ab + cd + pq <3 (3) ab + cd + pq >= 3 (4) ab + cd + pq <= 3/2​.

Answers

Answered by Anonymous
9

QUESTION:-

Given a2 + b2 = 1, c2 + d2 = 1, p2 + q2 = 1,where all numbers are real, then

(1) ab + cd + pq >= 1 (2) ab + cd + pq <3 (3) ab + cd + pq >= 3 (4) ab + cd + pq <= 3/2.

ANSWER:-

Given a2 + b2 = 1, c2 + d2 = 1, p2 + q2 = 1,where all numbers are real, then

(1) ab + cd + pq >= 1 【✔️】 (2) ab + cd + pq <3【❌】 (3) ab + cd + pq >= 3【❌】 (4) ab + cd + pq <= 3/2.【❌】

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Answered by brainlyqueen1237
21

\huge\bold\star\underline\mathbb\orange{Answer\: :)}

Given a2 + b2 = 1, c2 + d2 = 1, p2 + q2 = 1,where all numbers are real, then

(1) ab + cd + pq >= 1 【✔️】

(2) ab + cd + pq <3 【❌】

(3) ab + cd + pq >= 3 【❌】

(4) ab + cd + pq <= 3/2.【❌】

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