Given AB = AD and AC bisects BC.
Prove Triangle ABC is congruent toTriangle ADC
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Answered by
3
proof
AB=AD(GIVEN)
AC=AC(COMMON)
BC=CD(GIVEN THAT BC IS BISECTED)
by SSS congruence rule
ABC is congruent to ADC
AB=AD(GIVEN)
AC=AC(COMMON)
BC=CD(GIVEN THAT BC IS BISECTED)
by SSS congruence rule
ABC is congruent to ADC
Answered by
0
FROM ΔABC and ΔACD
AB = AD (GIVEN)
AC = AC (COMMON)
BC = CD (AC BISECTS BD)
by SSS congruence
ΔABC ≡ ΔACD
hence proved
AB = AD (GIVEN)
AC = AC (COMMON)
BC = CD (AC BISECTS BD)
by SSS congruence
ΔABC ≡ ΔACD
hence proved
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