Question

Given
ABAD, BCCD, BAD110O, BDC40O
, Calculate i)ABC ii)BCD

Answer 1

Answer:

(i)angle ABC = 70 (ii) angle BCD=30

Explanation:

angles opposite to equal sides are are equal

angle ABD =40

from triangle ABD

110+40+a =180

150+a=180

a=180-150

a=30

ADB = DBC (opposite angles are equal)

so,

angle DBC is 30

angle ABC = angle ABD+DBC

angle ABC=40+30

angle ABC=70

from triangle DBC

angle DBC+BCD+CDA = 180 ( anglesum property)

30+x+40 =180

70+x=180

X=180-70

X=110

so

(i)ABC=70 (ii) BCD=30

hope this helps