Given AB ANGLE B , AC. .. ANGLE E AND DE. .in the triangle ABC..
Find the area of triangle ADE.
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hey mate here is your answer
in triangle ABC by Pythagoras theorem
ac²=ab²+bc²
BC=√(15²-12²)
=✓225-144=√81=9cm
now in triangle ABC and triangle ade
ade=ABC........90
a=a.....ca
ade~abc......a
so by cpct
ae/ac=de/BC
ae=3/9×15
=5cm
now area of triangle ade=1/2×b×h
=1/2×3×5
=7.5cm²
hope it will help you
mark me brainliest
in triangle ABC by Pythagoras theorem
ac²=ab²+bc²
BC=√(15²-12²)
=✓225-144=√81=9cm
now in triangle ABC and triangle ade
ade=ABC........90
a=a.....ca
ade~abc......a
so by cpct
ae/ac=de/BC
ae=3/9×15
=5cm
now area of triangle ade=1/2×b×h
=1/2×3×5
=7.5cm²
hope it will help you
mark me brainliest
vampire002:
it is correct sir
Answered by
1
Answer:
Hey here's your answer,
In triangle ABC by Pythagoras theorem
ac²=ab²+bc²
BC=√(15²-12²)
=✓225-144=√81=9cm
so by cpct
ae/ac=de/BC
ae=3/9×15
=5cm
Now area of triangle ADE=1/2×b×h
=1/2×3×5
=7.5cm²
Happy to help... Hope it helps. plz mark as brainliest
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