Question

Given AB ANGLE B , AC. .. ANGLE E AND DE. .in the triangle ABC..

Find the area of triangle ADE.

Answer 1

hey mate here is your answer
in triangle ABC by Pythagoras theorem
ac²=ab²+bc²
BC=√(15²-12²)
=✓225-144=√81=9cm
now in triangle ABC and triangle ade
ade=ABC........90
a=a.....ca
ade~abc......a
so by cpct
ae/ac=de/BC
ae=3/9×15
=5cm
now area of triangle ade=1/2×b×h
=1/2×3×5
=7.5cm²
hope it will help you
mark me brainliest

Answer 2

Answer:

Hey here's your answer,

In triangle ABC by Pythagoras theorem

ac²=ab²+bc²

BC=√(15²-12²)

=✓225-144=√81=9cm

so by cpct

ae/ac=de/BC

ae=3/9×15

=5cm

Now area of triangle ADE=1/2×b×h

=1/2×3×5

=7.5cm²

Happy to help... Hope it helps. plz mark as brainliest