Given AB // CD/ EGB = 35° and QP ER
then find /PQ
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Hi ,
It is given that ,
AB // CD , EF is the transversal .
i ) <CGH = <GHB [ alternate angles ]
y = 3x ----( 1 )
<EGC + <CGH = 180° [ Linear angles ]
2x + y = 180---( 2 )
2x + 3x = 180 [ from ( 1 ) ]
5x = 180
x = 180/5
x = 36°
Put x value in equation ( 1 ) , we get
y = 3 × 36 = 108°
ii ) <EGD = GHB [ Corresponding Angles ]
2x + 15 = 3x - 20
15 + 20 = 3x - 2x
35 = x
x = 35°
iii ) <DGH + <DHB = 180°
[ Sum of interior angles same side of the
transversal ]
4x - 23 + 3x = 180°
7x = 180 + 23
7x = 203°
x = 203/7
x = 29°
I hope this helps you.
: )
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