Question

Given AB II CD and AD II BC, what is the value of x​

Answer 1

Answer:

x= 120°

Step-by-step explanation:

since ab||cd,

abcd is a parralelogram

40° = D - 90°

therefore,

D = 130°

adjacent angles of a parralelogram are supplementary:

130° + c = 180°

C = 50°

therefore

50° + x = 180°

x = 130°

Answer 2

Step-by-step explanation:

In the given figure,

Angle DOA= Angle EOB (vertically opposite angles)

Angle DOA= 40°

In triangle DAO,

Angle ADO+Angle DAO+ Angle DOA= 180°(Angle sum property)

=) 90°+Angle DAO+ 40°= 180°

=) Angle DAO+90°+40° =180°

=) Angle DAO+ 130° = 180°

=) Angle DAO= 180°-130°

=) Angle DAO= 50°

In ABCD,

Angle DCB= Angle DAO (opposite angles of a parallelogram are equal)

Angle DCB= 50°

Now,

Angle DCB+ Angle DCH= 180° (linear pair)

=)50°+x= 180°

=) x = 180°-50°

=) x = 130°

Therefore the value of x is 130°

HOPE IT HELPS YOU.