given AB IS PERPENDICULAR TO BC DE IS PERPENDICULAR TO BC AB 9CM DE 3CM AC 25 CM FIND AD USING PYTHAGORAS THEOREM
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Answer:
GIVEN:
(AB)perp.(BC)
(DE)perp. (BC)
DE=3cm
AC= 25cm
find AD using pythagoras theorem
ANSWER:
sorry i didnt
take it yet
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