given AB IS PERPENDICULAR TO BC DE IS PERPENDICULAR TO BC AB= 9CM DE =3CM AC =25 CM FIND AD
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Answered by
0
Answer:
Step-by-step explanation:
Given, ∠ABC=∠DEC=90
∘
In △ABC and △DEC,
∠ABC=∠DEC (Each 90
∘
)
∠ACB=∠DCE (Common)
∠BAC=∠CDE (third angle)
Thus, △ABC∼△DEC
Hence,
DE
AB
=
DC
AC
3
9
=
24−AD
24
24−AD=8
AD=16 cm
Answered by
1
Answer:
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