Question

Given: ∆ABC~∆PQR AB/PQ = 1/3
To find: ar∆ABC / ar∆PQR

Answer 1

GIVEN:
ΔABC ~ Δ PQR & AB/PQ = 1/3
ar(ΔABC)/ar( Δ PQR )= AB²/ PQ²
[The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.]
ar(ΔABC)/ar( Δ PQR ) = 1²/3²
[Given =AB/PQ = ⅓]
ar(ΔABC)/ar( Δ PQR ) = 1/9
Hence, the Area of ΔABC/Area of ΔPQR = 1/9

HOPE THIS WILL HELP YOU….

Answer 2

Hi Mate !!


Given :- ∆ABC ~ ∆PQR

AB /PQ = 1/3

• Ratio of area of similar ∆'s are equal to the ratio of square of their corresponding side


area of ∆ ABC/ area of ∆PQR = AB²/PQ²


area of ∆ ABC/ area of ∆PQR = 1/9