Question

Given ∆ ABC ~∆PQR , if AB / PQ = 1/3 then find ar∆ ABC /ar∆PQR

Answer 1

We know that ratio of two similar triangle is equal to the square the ratio of corresponding side.
so ar.abc/ar.pqr= (AB)^2/(PQ)^2
                           = (1/3)^2
                          = 1/9

Answer 2

Given:

ABC and PQR are similar triangles.

$\frac{A B}{P Q}=\frac{1}{3}$

To find:

The ratio of area of triangle ABC and area of triangle PQR

Solution:

$\frac{A B}{P Q}=\frac{1}{3}$

The ratio of the areas of two similar triangles is equal to the square of ratios of corresponding sides.

$\frac{{area}(A B C)}{{area}(P Q R)}=\left(\frac{A B}{P Q}\right)^{2}$

$\frac{{area}(A B C)}{{area}(P Q R)}=\left(\frac{1}{3}\right)^{2}$

$\frac{{area}(A B C)}{{area}(P Q R)}=\frac{1}{9}$

To learn more...

1. Given triangle ABC ~ triangle PQR AB/PQ =1/3 then find the area of triangle ABC/ triangle PQE

https://brainly.in/question/3098344

2. Given ABC~ PQR, if AB/PQ=1/3,then find ar ABC/ar PQR

brainly.in/question/3128361