GIVEN △ABC ~ △PQR, if AB/PQ =1/3, then find ar△ABC/ ar△PQR
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TRIANGLE ABC SIMILAR TO TRIANGLE PQR.
AB/PQ = 1/3.
WE KNOW THAT THE RATIO OF THE AREA OF TWO SIMILAR TRIANGLE IS EQUAL TO THE SQUARE OF IT'S CORRESPONDING SIDE.
THEREFORE,
AR(ABC)/AR(PQR) = (AB/PQ)²
AR(ABC)/AR(PQR) = (1/3)²
AR(ABC) / AR(PQR) = 1/9
THEREFORE,
THE RATIO OF THE AREA OF TWO SIMILAR TRIANGLE ABC AND PQR = 1:9
AB/PQ = 1/3.
WE KNOW THAT THE RATIO OF THE AREA OF TWO SIMILAR TRIANGLE IS EQUAL TO THE SQUARE OF IT'S CORRESPONDING SIDE.
THEREFORE,
AR(ABC)/AR(PQR) = (AB/PQ)²
AR(ABC)/AR(PQR) = (1/3)²
AR(ABC) / AR(PQR) = 1/9
THEREFORE,
THE RATIO OF THE AREA OF TWO SIMILAR TRIANGLE ABC AND PQR = 1:9
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