Given ∆ABC ~∆PQR,if AB/PQ = 1/3, then find ar ∆ ABC / ar ∆ PQR.
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1:9
by theorem of area of triangle given in ncert textbook
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by theorem of area of triangle given in ncert textbook
if you liked it then please make this brainliest
Panwadi:
The answer is 1/9
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∵ Δ ABC ≈ Δ PQR
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = ( AB/PQ)²
( According to the theorem on similarity of triangles)
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = ( 1/3)²
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = 1 / 9
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = ( AB/PQ)²
( According to the theorem on similarity of triangles)
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = ( 1/3)²
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = 1 / 9
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