Question

Given ABC~ PQR, if AB/PQ=1/3,then find AR ABC/ar PQR

Answer 1

ar (abc)/ar (pqr) = ab$^{2}$/pq$^{2}$ 

=> 1/9

Answer 2

we know that the ar of triangle is square of its congurent

AP / PQ = 1/ 3

area ABC / area PQR = (AB / PQ )^2
= (1/3)^2
= 1/9

HOPE ITS HELP
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thnks and best of luck for re-exam☺