Given ∆abc ~∆pqr if ab/pq=1/3 then find ar∆abc/ar∆pqr
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given data...
the area of ABC/
area of pqr = (ab)sq/ (pq)sq
=(1/3) sq
1sq/ 3sq
1/9
the area of ABC/
area of pqr = (ab)sq/ (pq)sq
=(1/3) sq
1sq/ 3sq
1/9
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