Given ∆ABC ~ ∆PQR, If BC/QR = 2/5, Then ar(∆ABC)/ar( ∆PQR) =?
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ratio of area of similar triangles is equal to ratio of square of their corresponding sides.
so, ar(ABC)/ar(PQR) = (BC/QR)²
ar(ABC)/ar(PQR) = (2/5)² = 4/25 = 4:25
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1
Answer:
4/25
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