Math, asked by Anuragkkumar2006, 6 hours ago

Given ∆ABC ~ ∆PQR, If BC/QR = 2/5, Then perimeter of (∆ABC)/ perimeter of ( ∆PQR) =?​

Answers

Answered by sanvimaurya4
16
Perimeter of ABC / perimeter of PQR = BC /QR
=> Perimeter of ABC / perimeter of PQR =2/5
Answered by anjumanyasmin
17

Given:

∆ABC ~ ∆PQR

BC/QR = 2/5

Find perimeter of (∆ABC)/ perimeter of ( ∆PQR) =?​

  • We know that the ratio of the perimeter of two similar triangle is equal to the ratio of their corresponding sides.
  • So perimeter of ∆ABC and perimeter of ∆PQR is equal to the ratio of their side BC and QR

So here

\frac{Perimeter \ of \triangle \mathrm{ABC}  }{Perimeter \ of \triangle \mathrm{PQR} }=\frac{BC}{QR}

\frac{Perimeter \ of \triangle \mathrm{ABC}  }{Perimeter \ of \triangle \mathrm{PQR} }=\frac{BC}{QR}=\frac{2}{5}

Hence the answer is 2/5cm

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