Question

Given acceleration a = t+1 find x at 1 sec given initial velocity = 2 m/s and initial displacement 1

Answer 1

a = t+1 = dv/dt

so
v = t²/2 + t + 2 = dx/dt
[2 because v=2 at t=0]

so
x = t³/6 + t²/2 + 2t + 1


hope it helps you
@di