Question

given
af is a tangent to a cirlce at b, o is the centre, ∠fbc=55°, ∠eab=30°
find ∠bcd, ∠bed, ∠bdc
CORRECT ANSWER WILL BE GIVEN BRAINLIEST
Wrong ANSWERS ARE STRICTLY NOT ALLOWED

Answer 1

Answer:

refer to the given attachments....

PLEASE MARK AS THE BRAINLIEST.....

Answer 2

Answer:

/_BDC = /_FBC [Alternate segment theorem]

/_BDC = 55°

/_BDC = /_DBC [CB = CD, radii of same circle. Opposite angles of equal sides]

/_DBC = 55°

/_BCD + /_DBC + /_BDC = 180° [Angle Sum Property]

/_BCD = 180 - 55 - 55

/_BCD = 70°

/_BCD + /_BED = 180° [Opposite angles of a cyclic quadrilateral]

/_BED = 110°

___________