Question

given an=a+2n write first 3 terms​

Answer 1

Answer and Explanation

$\implies$ Given that,

nth term = aₙ = a + 2n

$\implies$ First term

a₁ = a + 2*1

a₁ = a + 2

$\implies$ Second term

a₂ = a + 2*2

a₂ = a + 4

$\implies$ Third term

a₃ = a + 2*3

a₃ = a + 6

a₁ = a + 2

a₂ = a + 4

a₃ = a + 6

Hence,

Common difference = a₂ - a₁ = (a + 4) - (a + 2) = a + 4 - a - 2 = 2

                              d = a₃ - a₂ = (a + 6) - (a + 4) = a + 6 - a - 4 = 2

Answer 2

Answer:

a+2, a+4, a+6

Step-by-step explanation:

given- an=a+2n....(1)

we have to find $a_{1} , a_{2} , a_{3}$

let n be 1

putting n = 1 in (1)

$a_{1}$ = a+2(1)

$a_{1}$ = a+2

similarly putting n=2 in(1)

we get $a_{2}$ = a+4

and putting n=3 in (1)

we get $a_{3}$ = a+6