Given an = an − 1 − 6an−2 where a0 = 1 , a2 = 5
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Solve the recurrence relation an = 6an-1 − 9an-2, with initial conditions a0 = 1, a1 = 6. Exercise: Solve the recurrence relation an = 6an-1 − 9an-2, with initial conditions a0 = 1, a1 = 6. Solving these equations we get α1 = 1 and α2 = 1. Therefore, an = 3n + n3n.
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