Question

Given an AP such that Sn=n(5n-3) for every n.Find the 10th term of this progression.

Answer 1

Answer:

92

Step-by-step explanation:

Sₙ = n(5n-3)

    = 5n²-3n

We can find first term and common difference from equation itself.

if the equation is of sum,

common difference,d = double the coefficient of n²

                                 = 2x5

                                 = 10

first term,f = sum of all coefficients

               = 5+-3

               = 5-3

               = 2

algebriaic expression of sequence = dn+(f-d)

                                                     = 10n+(2-10)

                                                     = 10n+ -8

                                                     = 10n-8

to find tenth term , put n = 10 in 10n-8

10th term = 10x10 - 8

              = 100-8

              = 92

Answer 2

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