Question

Given an email address, extract the username by eliminating the and the subsequent characters to form a new string Str. Add the length of at the end of Str to form a resultant string R

Read the input from STDIN and print the output to STDOUT. Do not write arbitrary strings while reading the input or while printing, as these contribute to the standard

output

42 €

Constraints:

Length of email address 100

Username U can contain an alphanumeric string

Input Format:

The input contains the email address.

Output Format:

The output contains R.

Sample Input1; [email protected]

Sample Output1: AbcDefGhi9

Explanation1:

By eliminating "@" from the email address '[email protected], the user name U becomes 'AbcDefGhi", and the length of U is 9. Thus, the output is AbcDefGhi9.

Sample Input2: [email protected]

Sample Output2: XYZ123abc510

Explanation 2:

The user name here is XYZ123abc5, and the length of the​

Answer 1

Answer:

username by eliminating the and the subsequent characters to form a new string Str. Add the length of at the end of Str to form a resultant string R

Read the input from STDIN and print the output to STDOUT. Do not write arbitrary strings while reading the input or while printing, as

Sample Input1; AbcDefGhi@

Answer 2

Answer:

email=input("enter the email\n")

# original string is printed

print("The original string is : " + str(email))

# slicing domain name using slicing

res = email[:email.index('@') ]

# finding the length of the sliced string

length_of_the_string=len(res)

final_string=res+str(length_of_the_string)

# printing result

print("The extracted username with lenght is : " + str(final_string))

Explanation:

• Initially, a string is taken as input from the user.
• Then it is sliced until the cursor meets the character "@".
• The content after the @ is cut out and the remaining string is taken for consideration.
• The length of the remaining string is concatenated with the length for the result.

#SPJ2