Question

Given an equilateral triangle t1 having side 24 an another traingle t2 is created by joinign mid points of its sodes

Answer 1

Answer:

As P,Q and R are mid points of AC,AB and BC so both triangle PQR and CBA will be similar and PQ = BC/2

So if the area of triangle ABC = A then area of triangle PQR = A/4

Thus

Sum of Areas = A+A/4+A/16+A/64+ ——–=A/(1-1/4)=4/3 A=4/3×√3/4×24^2=192√3