Math, asked by jyoti337, 1 year ago

Given an exponential function for compounding interest, a(x) = p(1.03)x, what is the rate of change?

Answers

Answered by danielochich
1
The rate of change is found by differentiating the function:

a(x) = p(1.03)^x


d/dx a^x = a^x ln(a)


d/dx (
p(1.03)^x) = p(1.03)^x ln 1.03


                          = 0.03p(1.03)^x



NOTE:

Derivatives/derived functions give the rates of change.


Answered by Anonymous
0

Answer:

Step-by-step explanation:

The rate of change is found by differentiating the function:

a(x) = p(1.03)^x

d/dx a^x = a^x ln(a)

d/dx (p(1.03)^x) = p(1.03)^x ln 1.03

= 0.03p(1.03)^x

NOTE:

Derivatives/derived functions give the rates of change.

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