Given an isosceles trapezium ABCD in order with AB = 6, CD = 12 and area 36 sq. units. Length of the
side BC is:
दिये गये समद्विबाहु समलंब चतुर्भुज ABCD में AB%3D6,CD = 12 और उसका क्षेत्रफल 36 वर्ग इकाई है। मुजा BC की
लम्बाई होगी।
(A)6
(B)5
(C)4.5
(D)5.5
Answers
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area of trapezium
= 1/2× sum of parallel sides ×distance between them
36=9×distance between them
lenght= 4 ans
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