Question

given an right angle abc right angle at c in which tanA= √3 tanB =1/√3 show that sinA-cosB-cosA sinB =1/2

Answer 1

Answer:

i dont know

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

tanA=√3 (given)

tan 60°=√3

⇒∠A=60°

tanb=1/√3 (given)

tan30°= 1/√3

⇒∠B=30°

∴sina-cosb-cosa·sinb=sin60°-cos30°-cos60°·sin30°

=√3/2-√3/2-1/2·1/2

=0-1/4

=-1/4.