Given angle aoc =110° then find angle Acd
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ʜᴏᴘᴇs ᴛʜᴇ ᴀʙᴏᴠᴇ ᴀᴛᴛᴀᴄʜᴇᴅ ᴘɪᴄ ʜᴇʟᴘs ᴜ
ᴇxᴀᴍᴘʟᴇ
We know that the angle subtended by an arc is twice the angle subtended by it on the circumference in the alternate segment.
Thus, ∠AOC = 2∠ADC
⇒ 100° = 2∠ADC
∴ ∠ADC = 50
The oppositeangles of a cyclic
quadrilateral are supplementary and
ABCD is a cyclic quadrilateral.
Thus, ∠ADC +∠ABC = 180°
⇒ 50° + ∠ABC = 180°
⇒ ∠ABC = (180° – 50°) = 130
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