Question

Given: Angle B is congruent to Angle D and Line AD is parallel to Line BC

Prove: Triangle ABC is congruent to Triangle CDA

Please help! I really need it!

Answer 1

Answer:

In triangles ADC and CBA, we have

AB=CD-(given);

AD=BC - (given);

AC=AC -(common side).

By S.S.S congruency condition,

△ADC≅△CBA [henceproved]

Answer 2

Answer:

This can be proved

Step-by-step explanation:

but pls can you paste the question figure with this.

I think It will bb proved by SAS

BECAUSE THEY ARE PARALLEL SO THE ANGLE THEY MADE WILL BE EQUAL AS WELL AS SIDE ALSO