Question

given: angle CAB=75°
and angle CBA=50°
Find the value of angle DAB + angle ABD

Answer 1

This is your answer... May this help you

Answer 2

Hence value of angle DAB + angle ABD is 125°

Step-by-step explanation:

Given:

Here, ∠CAB = 75°, CBA=50°

In Δ ABC,

∠CBA + ∠ACB + ∠BAC = 180°                 (by angle sum of property)

50° + ∠ACB + 75° = 180°                              (given)

∠ACB + 125° = 180°        

∠ACB = 180° - 125°

∠ACB = 55°

∠ ADB = ∠ ACB = 55°   ( angle subtended by an arc in the same segment are equal)                    [1]

Now,

In Δ ADB,

∠ ADB + ∠ BAD + ∠ ABD = 180°             ( by angle sum property)

55° + ∠ BAD + ∠ ABD = 180°                        [ from 1 ]

∠ BAD + ∠ ABD = 180° - 55°

∠ BAD + ∠ ABD = 125°

Hence value of angle DAB + angle ABD is 125°