Question

given angle POR =4x and angle QOT=x+10°find the value of x for which POW will be a straight line​

Answer 1

x + 10° + 4x = 180 (sum of angles of a straight line is 180°)

5x =170°

x = 34°

Therefore the 2 angles are,

x + 10° = 44°

4x = 136°

Answer 2

Answer:

angle POR+angle QOR=180°(linear pair angle)

4x+x+10°=180°

5x=170°

x=170/5

x=34°