Question

Given any n digit number ending with 1 raise to any power p. What will be the last 2 digits of the resultant number.

Answer 1

To find the last two digits of any number whose unit digit is 1 is as follows-

Trick-

• The tens digit of the resultant product=

unit digit of power × tens digit of base.

• The unit digit of the resultant= 1 ( as one multiplied by one will always make one no matter how many times they are multiplied.)

let us take an example

31^46

=> 6(unit digit of power)× 3(tens digit of base)

=> 18

so, 8 is the tense digit of the resultant.

8,1 are the last two digits of the resultant number.