given AO is perpendicular on OB find angle BOC
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here the answer is............
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pala3377:
hi
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The angle BOC = 25°
Given:
AO is perpendicular on OB
To find:
The measure of angle BOC
Solution:
From given figure,
∠AOC = (2x-5)° and ∠COB = (x-10)°
Given that AO is perpendicular on OB
Then ∠AOB = 90°
Here, ∠AOB = ∠AOC + ∠COB
⇒ ∠AOC + ∠COB = 90°
As we know ∠AOC = (2x-5)° and ∠COB = (x-10)°
⇒ (2x-5)° + (x-10)° = 90°
⇒ 3x -15° = 90°
⇒ 3x = 105°
⇒ x = 35°
Therefore, (x-10)° = 35° - 10° = 25°
The angle BOC = 25°
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