Given are three numbers. If the second and third numbers, respectively, are 25%and 50% more than the first, then what percentage of the second is the third?
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solution:
Let third number is X.
Then first no = 20% of X = 20X/100
Second number = 50% of X = 50X/100
Percent of first no of second no,
= [(20X/100)/(50X/100)] * 100 = (2*100)/20 = 40%.
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