Math, asked by pratikshahagavane24, 7 months ago

Given arithmetic progression 12,16,20,24,....... Find the 30 th term of this progression. *​

Answers

Answered by shan650500
0

Answer:

A30 = 128

Step-by-step explanation:

a= 12 , d= 16-12=4 ,n =30

=> an = a+(n-1)d

=> an = 12+(30-1).4

=> an = 12+(29× 4)

=> an = 12+116

=> an = 128

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