Question

Given arithmetic progression 9,13,17,21 find the 12th term and 24th term of this progression​

Answer 1

therefore 12th term and 24th term of given A.P. is 53 and 101 respectively

Answer 2

Answer:

The difference between progression is 4

Then, first term 9

=> 9 ÷ 4 = Quotient = 2 ; Remainder = 1

=> 9 = ( 4 × ( term + 1 ) + 1 )

=> 9 = ( 4 × 2 ) + 1

then, 12th term

=> ( 4 + ( 12 + 1 ) + 1 )

=> ( 4 × 13 ) + 1

=> 52 + 1

=> 53

24th term

=> ( 4 × ( 24 + 1 ) + 1 )

=> ( 4 × 25 ) + 1

=> 100 + 1

=> 101

You can also use arithmetic progression formula. I explain in detail.

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