Question

Given ,Avector =2icap +3jcap and Bvector=icap +jcap.Find the magnitude of projection of Avector along Bvector

Answer 1

Answer:

$\frac{5}{ \sqrt{2} }$

Explanation:

A=2i^ +3j^

B= i^ + j^

projection of A along B is equal to

|A|cos(theta)

where (theta) is the angle between A and B.

we know,

A.B= |A| |B| cos(theta)

|A| cos(theta)= (A.B)/|B|

A.B = 2+3=5

|B|= (1²+1²)^½=2^½

|A| cos(theta)= (A.B)/|B|

= 5/(2^½)