given below a pair of simultaneus equation,
4x+y=14
2x-3y=0
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Q. In (II) there should have been 2x - 3y = 12
5x + 3y = 9 -----(I)
5x + 3y = 9 -----(I)2x - 3y = 12 ----- (II)
Add (I) and (II)
- 7x = 21
- 7x = 21x = 3
- 7x = 21x = 3Putting the value of x = 3 in (I) we get
- 7x = 21x = 3Putting the value of x = 3 in (I) we get5(3)+3y=9⇒15+3y=9⇒3y=9-15=-6⇒y=-2
- 7x = 21x = 3Putting the value of x = 3 in (I) we get5(3)+3y=9⇒15+3y=9⇒3y=9-15=-6⇒y=-2Thus, (x, y) = (3, -6).
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this is the perfect and correct answer of this question.
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