given below are the ages of 45 , People in a colony 33, 8 , 7 , 25, 31 , 26, 5, 50, 25, 48, 56, 33, 28,22, 15,62, 59 , 16,14,19, 24, 35, 26,9,12,46,15,42,63,32,5,22, 11, 42, 23, 52, 48, 62 , 10, 24, 43 , 51, 37, 48 , 36, 3 . Construct a frequency distribution for the given data with 6 class interval .
Answers
Answer:
Since, we have been provided with some ages of the people,
We have to group all those , ages among the number of people and we have to construct a frequency distribution table for the given data.
Note that we will be considering as a gap of 6 class interval.
So, we will be starting the ages from 3 , because no ages of people are less than 3.
So, here we are representing the frequency distribution table.
Ages No. of people
3 - 9 6
10 - 16 6
17 - 23 4
24 - 30 7
31 - 37 7
38 - 44 3
45 - 51 6
52 - 58 2
59 - 65 4
So , we have constructed a frequency distribution table as given above.