Math, asked by nutteyy1904, 1 year ago

given below are the ages of 45 , People in a colony 33, 8 , 7 , 25, 31 , 26, 5, 50, 25, 48, 56, 33, 28,22, 15,62, 59 , 16,14,19, 24, 35, 26,9,12,46,15,42,63,32,5,22, 11, 42, 23, 52, 48, 62 , 10, 24, 43 , 51, 37, 48 , 36, 3 . Construct a frequency distribution for the given data with 6 class interval .

Answers

Answered by ameena29
47
this is the correct answer
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Answered by suchindraraut17
28

Answer:

Since, we have been provided with some ages of the people,

We have to group all those , ages among the number of people  and we have to construct a frequency distribution table for the given data.

Note that we will be considering as a gap of 6 class interval.

So, we will be starting the ages from 3 , because no ages of people are less than 3.

So, here we are representing the frequency distribution table.

          Ages                            No. of people

           3 - 9                                    6

          10 - 16                                   6  

          17 - 23                                   4

          24 - 30                                  7

          31 - 37                                    7

          38 - 44                                   3

          45 - 51                                   6

           52 - 58                                 2

            59 - 65                                4

So , we have constructed a frequency distribution table as given above.

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