given below are the length of the legs of a right ∆abc. in each case, find the length of the hypotenuse of ∆abc : (¡) a=32cm, b= 60cm (¡¡) a=28m, b=24m (¡¡¡) a=32cm, b=24cm
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Triangles
Pythagoras Theorem and its Converse
In right ABC , the lengths...
In right △ABC, the lengths of its legs are given as a=6cm and b=4.5cm. Find the
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Let AB=10cm
Hypotenuse (AC)=26cm
BC=?
Then, by Pythagoras theorem
AC2=AB2+BC2
c2=a2+b2
c2=62+(4.5)2
c2=36+20.25
c2=56.25
Sending powers 2 from LHS to RHS it becomes square root
c=56.25
c=7.5cm
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