Given below are three quations. Two of them have infinite solutions and two have a unique solution. State two pairs: 3x-2y=4; 6x+2y=4: 9x-6y=12
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1) Infinite Solutions:
3 x - 2 y = 4 and 9 x - 6 y = 12
As they satisfy a₁/a₂ = b₁/b₂ = c₁/c₂
⇒ 3/9 = -2/-6 = 4/12
⇒ 1/3 = 1/3 = 1/3
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2) Unique solution:
3 x - 2 y = 4 and 6 x + 2 y = 4
As they satisfy a₁/a₂ ≠ b₁/b₂
⇒ 3/6 ≠ -2/2
⇒ 1/2 ≠ -1
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☺☺☺ Hope this Helps ☺☺☺
3 x - 2 y = 4 and 9 x - 6 y = 12
As they satisfy a₁/a₂ = b₁/b₂ = c₁/c₂
⇒ 3/9 = -2/-6 = 4/12
⇒ 1/3 = 1/3 = 1/3
__________________________________________________________
2) Unique solution:
3 x - 2 y = 4 and 6 x + 2 y = 4
As they satisfy a₁/a₂ ≠ b₁/b₂
⇒ 3/6 ≠ -2/2
⇒ 1/2 ≠ -1
__________________________________________________________
☺☺☺ Hope this Helps ☺☺☺
nitthesh7:
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