Math, asked by arnaviraviprakash, 1 day ago

Given below is the sequence of numbers 4, 7, 10, 13, 16, 19, 22... The first number in the sequence is 4 and the third number is 10. What will be the mth number in the sequence?

Answers

Answered by ranaayush5903
19

Step-by-step explanation:

Here it is

4+3=7

7+3=10

10+3=13

13+3=16

16+3=19

19+3=22

22+3=25

25+3=28

and so on...(add the numbers by 3 )

Hope.you.are.satisfied.

Answered by tennetiraj86
38

Answer:

3m+1

Step-by-step explanation:

Given :-

The sequence 4,7,10,13,16,19,22,...

To find :-

m th number

Solution :-

Given sequence is 4,7,10,13,16,19,22,...

First term (a) = 4

Second term (a2) = 7

Common difference (d) = 7-4 = 3

d = 10-7 = 3

d = 13-10 = 3

d = 16-13 = 3

d = 19-16 = 3

d = 22-19 = 3

Since the common difference is same through out the sequence , It is an Arithmetic Progression.

Therefore, 4,7,10,13,16,19,22... are in the AP.

We have,

a = 4

d = 3

We know that

nth term of an AP (an ) = a+(n-1)d

Now,

mth term of the given AP

=> am = a+(m-1)d

=> am = 4+(m-1)(3)

=> am = 4+3m-3

=> am = (4-3)+3m

=> am = 1+3m

Therefore, am = 3m+1

Answer:-

mth term of the given AP is 3m+1

Used formulae:-

→ nth term of an AP (an ) = a+(n-1)d

  • a = First term
  • d = Common difference
  • n = Number of terms

Used Concept:-

If the common difference is same throughout the sequence then it is an Arithmetic Progression.

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