given below is the v-t graph for the motion of the car. find the acceleration. ( pls solve as the ans is 0.5m/s sq.)
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IN A VELOCITY-TUME GRAPH
ACCELEARATION = SLOPE OF GRAPH
> Slope of graph = (y2-y1) / (x2-x1)
y2 = 10
y1 = 0
x2 = 20
x1 = 0
ACCELERATION = (10-0) / (20-0)
=> 10/20
=> 0.5 m/sec square
ANSWER = 0.5 m/sec square
HOPE IT HELPS :=:)::):):):):););):)
MARK AS BRAINLIEST
ACCELEARATION = SLOPE OF GRAPH
> Slope of graph = (y2-y1) / (x2-x1)
y2 = 10
y1 = 0
x2 = 20
x1 = 0
ACCELERATION = (10-0) / (20-0)
=> 10/20
=> 0.5 m/sec square
ANSWER = 0.5 m/sec square
HOPE IT HELPS :=:)::):):):):););):)
MARK AS BRAINLIEST
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