Question

given by:
14.
AIIMS 2010
A charged conducting sphere has diameter 2.4 m
and surface charge density 10 C/m. Electric flux
passing through its surface will be :-
(1) 2 x 10 Nm?/C (2) 16 x 10' Nm?/C
(3) 1 x 10% Nm"/C (4) 2.2 x 10% Nm®/C
1​

Answer 1

Explanation:

ya this is too easy yrr

(a) Diameter of the sphere, d = 2.4 m

Radius of the sphere, r = 1.2 m

Surface charge density, = 80.0 μC/m2 = 80 × 10−6 C/m2

Total charge on the surface of the sphere,

Q = Charge density × Surface area

=

= 80 × 10−6 × 4 × 3.14 × (1.2)2

= 1.447 × 10−3 C

Therefore, the charge on the sphere is 1.447 × 10−3 C.

(b) Total electric flux () leaving out the surface of a sphere containing net charge Q is given by the relation,

Where, ∈0 = Permittivity of free space

∈0 = 8.854 × 10−12 N−1C2 m−2

Q = 1.447 × 10−3 C

= 1.63 × 108 N C−1 m2

Therefore, the total electric flux leaving the surface of the sphere is 1.63 × 108 N C−1 m2.