Question

Given CH4 plus CL2 gives CH3CL plus HCL . DELTA Hequals to -115 KJ. how much heat prouced during formation of 2.5kg of ch3cl

Answer 1

Answer:18×10³ KJExplanation:

ΔH=-115KJ/mole ⇒this is when 1 mole of CH4 is reacted i.e., 16 grams,

now how much for 2.5×10³ grams[∵balance eq is CH4+Cl2=⇒CH3Cl + HCl(this implies that to form 2.5 kg of CH3Cl we need 2.5 kg of CH4)]

16 grams⇒-115 KJ

2.5×10³ grams⇒?

∴heat produced=2.5×10³×(-115)/16≈18×10³ KJ