Question

given cos y = xcos(l+y). prove that dy/dx = cos^2(l+y)/sinl​

Answer 1

Step-by-step explanation:

cosy=xcos(1+y)

differentiating both sides

-siny dy/dx=cos(1+y) + (-sin(1+y))dy/dx

dy/dx(sin(1+y) -siny)=cos(1+y)

dy/dx(sin(1+y)cos(1+y)-siny)=cos^2(1+y)

dy/dx(sin1)=cos^2(1+y)

dy/dx=cos^2(1+y)/sin1