Given cot=7/8,then (1+sin)/cos
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Answer:
(√113+8)/7
Step-by-step explanation:
If we consider C as angle A
so that,cotC=7/8 | \
and BC=7 & AB=8 | \
tanC=8/7 & secC=√(113)/7 8 | \√(113)
|_ \
|_|_ \ =(1+sinC)/cosC B 7 C
=1/cosC + sinC/cosC
=secC + tanC
=√(113)/7 + 8/7
=(√113+8)/7
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