Given : cot A - Cos A / cot A + cos A is = cosec A - 1 / cosec A + 1 and sin 3A = Cos (A -26) degree. If 3A is an acute angle find the value of A.
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Sin3A=cos(A-26)
sin3A=sin(90-(A-26))
Both sides sin Cancelled
3A=90-(A-26)
3A=90-A+26
3A+A=90+26
4A=116
A=116/4
so,A=29°
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