Given cot q =
7/8
find;
(1 + sin theta] / cos theta
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Answered by
0
Answer:
1.15
Step-by-step explanation:
by pythagoras theorem
p²+b²=h²
cot q=b/p
so by this
b=7,p=8
so
h=sq.root of 7²+8²=10.63
now we know that
sin q=p/h
so
1+8/10.63=1.75
now
cos q=h/b
so
cos q=10.63/7=1.51
so by above equation we can find the value
(1+sin q)÷cos q=1.75/1.51=1.15
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