Question

Given cot theta=7/8 then(1+sin theta) (1-sin theta) /(1+cos theta) (1-cos theta) ​

Answer 1

Answer:

1/4

Step-by-step explanation:

take 1+sinthetha as sin thetha/2 × cos thetha/2

1+cos thetha as 2cos^2thetha /2

1-cos thetha as 2sin^2 thetha/2

and solve

Answer 2

Answer:

Hi friend,

given is cotθ=7/8 ⇒ opposite side = 8 and adjacent side=7 so, hypotenuse will be squareroot of sum of sqaures of 7 and 8 i.e sqrt7^2+8^2=√113 so now sinθ=8/√113 and cosθ=7/√113

(1+sinθ)(1-sinθ)/(1+cotθ)(1-cosθ)=1-sin^2θ/1+cotθ(1-cosθ)

                                                       = 1-64/113/1+7/8(1-7/√113)

on solving we get                         49/(√113-7)√113